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Quantum teleportation

A communication primitive that makes entanglement, measurement, and classical feed-forward explicit.

Strong empiricalUpdated

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A small worked example, computed in your browser. It is not a result from this record's papers.

Teleportation, deferred-measurement form

3 qubits, teleporting RY(π/3)|0⟩ from qubit 0 to qubit 2, with the corrections applied as controlled gates instead of classically controlled ones after a measurement.

q0q1q2Step 1 of 7 · RY(π/3)RY(π/3)Step 2 of 7 · HHStep 3 of 7 · CXCXStep 4 of 7 · CXCXStep 5 of 7 · HHStep 6 of 7 · CXCXStep 7 of 7 · CZCZ

Step 1 of 7 · RY(π/3)

⟨Z₂⟩ after this step1.00

  1. Prepares the state to teleport on qubit 0: RY(π/3)|0⟩.

    Probability spreads from 1 outcome to 2.

  2. Starts a Bell pair between qubit 1 (Alice's half) and qubit 2 (Bob's half).

    Probability spreads from 2 outcomes to 4.

  3. Completes the Bell pair.

    Probability moves: 2 outcomes appear that had none, 2 drop to zero, 4 carry probability now. Up: 110 0.0% → 37.5%. Down: 010 37.5% → 0.0%, 011 12.5% → 0.0%. This is the step that entangles the qubits: from here on no single qubit has a state of its own, only the register as a whole does.

  4. The first half of Alice's Bell measurement on her two qubits (0 and 1), ordinarily followed by an actual measurement.

    Probability moves: 2 outcomes appear that had none, 2 drop to zero, 4 carry probability now. Up: 011 0.0% → 12.5%, 101 0.0% → 12.5%. Down: 001 12.5% → 0.0%.

  5. The second half of Alice's Bell measurement.

    Probability spreads from 4 outcomes to 8.

  6. The correction that would classically depend on Alice's qubit-1 outcome, applied instead as a genuine controlled gate (the 'deferred measurement' trick).

    Probability moves between the same 8 outcomes. Up: 010 6.3% → 18.8%, 011 6.3% → 18.8%. Down: 110 18.8% → 6.3%.

  7. The correction that would classically depend on Alice's qubit-0 outcome, applied the same way.

    The outcome probabilities do not move at all. What this step changes is phase — 1 distinct relative phase across the state now — which no measurement can see until a later step turns it back into probability. The entanglement comes apart here: each qubit has a state of its own again.

Readout Qubit 2's marginal state matches RY(π/3)|0⟩ exactly: ⟨Z⟩ = cos(π/3) = 0.5. The state teleported across without qubit 0 and qubit 2 ever directly interacting.

Open in Studio
  • Steps3
  • Wires3
  • Qubits3
  • Classical bits2
  • Shared resourceBell pair
  • Papers1

A part this method uses, worked through

This page says Bell pair — here is a concrete, runnable instance of it.

A Bell pair

2 qubits, preparing (|00⟩ + |11⟩) / √2.

q0q1HCX

Where it ends up

  • 0050%
  • 1150%

Measuring both qubits always gives 00 or 11, each about half the time, and never 01 or 10.

Open this part in Studio

Teleportation moves an unknown state ∣ψ⟩=α∣0⟩+β∣1⟩|\psi\rangle=\alpha|0\rangle+\beta|1\rangle from Alice to Bob using one shared Bell pair and two classical bits. Alice holds ∣ψ⟩|\psi\rangle and her half of 12(∣00⟩+∣11⟩)\frac{1}{\sqrt2}(|00\rangle+|11\rangle); she applies CX then HH to the pair and measures both in the computational basis, obtaining classical bits (m1,m2)(m_1,m_2). Before measurement the three-qubit state can be written as an equal superposition over Alice's four outcomes, each pairing a Bell-basis result with a specific Pauli acting on Bob's qubit: 12∑m1,m2∣m1m2⟩⊗Zm1Xm2∣ψ⟩\frac{1}{2}\sum_{m_1,m_2}|m_1 m_2\rangle\otimes Z^{m_1}X^{m_2}|\psi\rangle. Bob applies Xm2Zm1X^{m_2}Z^{m_1} to undo that Pauli and recovers ∣ψ⟩|\psi\rangle exactly — the ideal-circuit result this record checks on a toy state. No information travels faster than light: Bob's qubit is maximally mixed until the two classical bits arrive, and the protocol consumes (does not clone) the input state, consistent with the no-cloning theorem.

References

Strong empirical
  • Verified by construction
  • Peer-reviewed paper
Method
Bell-pair preparation, Bell-basis measurement, and classically controlled corrections are checked on a toy state.
Result
Pass · the receiver recovers the input state in the ideal circuit.
Caveat
Teleportation transfers an unknown quantum state; it does not copy it or transmit information faster than light.
Teleporting an unknown quantum state via dual classical and EPR channels ↗
Kind
curated reference
Reviewed by
LeonaQ literature curation pass
License
Public bibliographic link; code is an original reference implementation
communicationentanglementnetworkingfeed-forward
  • Quantum repeater and network protocols
  • Remote gates and distributed quantum computing
  • Error-correction and lattice-surgery primitives

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